1/10y^2=-y-5/2

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Solution for 1/10y^2=-y-5/2 equation: 


y in (-oo:+oo)

(1/10)*y^2 = -y-(5/2) // + -y-(5/2)

(1/10)*y^2+y+5/2 = 0

1/10*y^2+y+5/2 = 0

DELTA = 1^2-(1/10*5/2*4)

DELTA = 0

y = -1/(1/10*2)

y = -5 or y = -5

y in { -5, -5 }

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